{"id":678620,"date":"2024-08-08T12:05:30","date_gmt":"2024-08-08T10:05:30","guid":{"rendered":"https:\/\/rothschenk.de\/epizoda-46-rozdeleni-hmotnosti-podle-kodu-cvut-5-nebo-10-nebo-60-40\/"},"modified":"2025-06-30T16:39:41","modified_gmt":"2025-06-30T14:39:41","slug":"epizoda-46-rozdeleni-hmotnosti-podle-kodu-cvut-5-nebo-10-nebo-60-40","status":"publish","type":"post","link":"https:\/\/rothschenk.de\/cz\/epizoda-46-rozdeleni-hmotnosti-podle-kodu-cvut-5-nebo-10-nebo-60-40\/","title":{"rendered":"Epizoda 46: Rozd\u011blen\u00ed hmotnosti podle k\u00f3du \u010cVUT 5 % nebo 10 % nebo 60\/40?"},"content":{"rendered":"\n

Rozlo\u017een\u00ed n\u00e1kladu v kontejnerech je v\u017edy p\u0159edm\u011btem diskus\u00ed. Na rozd\u00edl od star\u00fdch „Pokyn\u016f pro balen\u00ed CTU“ nen\u00ed Kodex CTU 2015 doporu\u010den\u00edm, ale z\u00e1vazn\u00fdm souborem pravidel obsahuj\u00edc\u00edm specifikace, kter\u00e9 je t\u0159eba dodr\u017eovat a kter\u00e9 lze tak\u00e9 kontrolovat. <\/p>\n\n

Jako p\u0159\u00edklad lze pou\u017e\u00edt sou\u010det mezer. Kontroln\u00ed pracovn\u00edk p\u0159epravn\u00ed spole\u010dnosti nebo p\u0159\u00edstavn\u00edho org\u00e1nu otev\u0159e kontejner, zm\u011b\u0159\u00ed vzd\u00e1lenost od zadn\u00edch dve\u0159\u00ed k n\u00e1kladu a pod\u00e1 st\u00ed\u017enost na zaji\u0161t\u011bn\u00ed n\u00e1kladu, pokud je vzd\u00e1lenost v\u011bt\u0161\u00ed ne\u017e 15 cm a nem\u016f\u017ee rozpoznat odpov\u00eddaj\u00edc\u00ed zaji\u0161t\u011bn\u00ed. Kontejner znehybn\u00ed nebo jej nech\u00e1 za poplatek opravit. <\/p>\n\n

Pokud je vzd\u00e1lenost ke dve\u0159\u00edm kontejneru v\u011bt\u0161\u00ed ne\u017e 60 cm, je pravd\u011bpodobn\u00e9, \u017ee kontejner byl nalo\u017een nespr\u00e1vn\u011b a nebyly dodr\u017eeny specifikace rozlo\u017een\u00ed n\u00e1kladu. Inspektor ani nemus\u00ed po\u010d\u00edtat, sta\u010d\u00ed, kdy\u017e vzd\u00e1lenost zm\u011b\u0159\u00ed, proto\u017ee podrobn\u00e1 kontrola mu pravd\u011bpodobn\u011b d\u00e1 za pravdu. <\/p>\n\n

Rozlo\u017een\u00ed zat\u00ed\u017een\u00ed je d\u016fle\u017eit\u00e9, proto\u017ee a\u010dkoli se ve velk\u00fdch modern\u00edch p\u0159\u00edstavech pou\u017e\u00edvaj\u00ed rozp\u011brky, kter\u00e9 kompenzuj\u00ed posun t\u011b\u017ei\u0161t\u011b na postroji, v pod\u0159\u00edzen\u00fdch p\u0159\u00edstavech tomu tak b\u00fdt nemus\u00ed. Tolerance bun\u011b\u010dn\u00fdch veden\u00ed, vodic\u00edch li\u0161t, po kter\u00fdch se kontejnery p\u0159es 9-11 vrstev kontejner\u016f zasouvaj\u00ed do trupu, je 4-5 cm. <\/p>\n\n

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Toto rozmetadlo dok\u00e1\u017ee kompenzovat odchylku t\u011b\u017ei\u0161t\u011b.<\/p>\n\n\n\n

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\"Rozmetadlo\n\t\t\t\n\t\t\t\t\n\t\t\t<\/svg>\n\t\t<\/button><\/figure>\n<\/figure>\n<\/div>\n<\/div>\n\n
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Tento rozv\u011bra\u010d to nedok\u00e1\u017ee, proto\u017ee silo\u010d\u00e1ry se sb\u00edhaj\u00ed v jednom bod\u011b h\u00e1ku.<\/p>\n\n\n\n

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\"Rozmetadlo-bez-kontejneru-distribuce-váhy-v-přístavu-červeně-ruční\n\t\t\t\n\t\t\t\t\n\t\t\t<\/svg>\n\t\t<\/button><\/figure>\n<\/figure>\n<\/div>\n<\/div>\n\n
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Jak je to s rozlo\u017een\u00edm z\u00e1t\u011b\u017ee?<\/strong><\/p>\n\n

Kodex CTU jasn\u011b specifikuje t\u011b\u017ei\u0161t\u011b v dodatku 7, bod 3.1.4:<\/p>\n\n

„Obecn\u011b plat\u00ed, \u017ee odchylka t\u011b\u017ei\u0161t\u011b b\u0159emene od st\u0159edu by nem\u011bla b\u00fdt v\u011bt\u0161\u00ed ne\u017e \u00b15 %. Obecn\u011b lze p\u0159edpokl\u00e1dat, \u017ee 60 % celkov\u00e9 hmotnosti n\u00e1kladu tvo\u0159\u00ed 50 % d\u00e9lky n\u00e1kladn\u00edho kontejneru. Za zvl\u00e1\u0161tn\u00edch okolnost\u00ed lze p\u0159ipustit odchylku a\u017e \u00b110 %, proto\u017ee modern\u00ed nakl\u00e1dac\u00ed za\u0159\u00edzen\u00ed pro manipulaci s kontejnery ISO je schopno tyto odchylky kompenzovat. P\u0159esnou polohu t\u011b\u017ei\u0161t\u011b v pod\u00e9ln\u00e9m sm\u011bru n\u00e1kladu lze vypo\u010d\u00edtat (viz dodatek 4). <\/em>„.<\/p>\n\n

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Situaci si lze sn\u00e1ze p\u0159edstavit v grafick\u00e9 podob\u011b.<\/p>\n<\/div>\n<\/div>\n\n\n\n

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\"Hmotnostní\n\t\t\t\n\t\t\t\t\n\t\t\t<\/svg>\n\t\t<\/button><\/figure>\n<\/figure>\n<\/div>\n<\/div>\n\n

Kodex CTU v odd\u00edle 4.2.2 na stran\u011b 18 ukl\u00e1d\u00e1 odes\u00edlateli povinnost informovat pronaj\u00edmatele (lodn\u00ed spole\u010dnost; dopravce) o v\u0161ech odchylk\u00e1ch t\u011b\u017ei\u0161t\u011b.<\/p>\n\n

Probl\u00e9mem, kter\u00fd nyn\u00ed stoj\u00ed p\u0159ed odpov\u011bdn\u00fdm nakladatelem, je ot\u00e1zka, jak tuto podm\u00ednku zajistit. \u0158e\u0161en\u00ed se naz\u00fdv\u00e1 pl\u00e1n ukl\u00e1d\u00e1n\u00ed! Ten se bohu\u017eel vytv\u00e1\u0159\u00ed jen z\u0159\u00eddka, co\u017e samoz\u0159ejm\u011b vede k probl\u00e9m\u016fm. Naklada\u010d obvykle za\u010d\u00edn\u00e1 s p\u011bkn\u00fdm, pohodln\u00fdm n\u00e1kladem vp\u0159edu a douf\u00e1, \u017ee v pr\u016fb\u011bhu ukl\u00e1d\u00e1n\u00ed p\u0159ijde na \u0159e\u0161en\u00ed probl\u00e9mov\u00e9ho n\u00e1kladu. Proto\u017ee tomu tak \u010dasto nen\u00ed, je v oblasti dve\u0159\u00ed a je to prvn\u00ed v\u011bc, kterou inspektor vid\u00ed. <\/p>\n\n

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Toto je vzorec z k\u00f3du \u010cVUT, kter\u00fd lze pou\u017e\u00edt k \u0159e\u0161en\u00ed probl\u00e9mu rozlo\u017een\u00ed z\u00e1t\u011b\u017ee. Jak\u00e1 o\u010dek\u00e1v\u00e1n\u00ed maj\u00ed auto\u0159i k\u00f3du \u010cVUT? N\u011bkter\u00e9 lidi odrad\u00ed vizu\u00e1ln\u00ed dojem ze vzorce. <\/p>\n<\/div>\n\n\n\n

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Vzorec je v\u0161ak snadno vysv\u011btliteln\u00fd. S\u00edlu, kterou p\u016fsob\u00ed ka\u017ed\u00e1 jednotliv\u00e1 jednotka zat\u00ed\u017een\u00ed, je t\u0159eba vypo\u010d\u00edtat podle principu p\u00e1ky. <\/p>\n\n\n\n

Jedn\u00e1 se o n\u00e1ro\u010dn\u00fd \u00fakol, kter\u00fd vy\u017eaduje znalost t\u011b\u017ei\u0161t\u011b a hmotnosti n\u00e1kladov\u00e9 jednotky. <\/p>\n\n\n\n

U b\u011b\u017en\u011b balen\u00fdch europalet lze obecn\u011b p\u0159edpokl\u00e1dat, \u017ee se nach\u00e1z\u00ed uprost\u0159ed. To znamen\u00e1 60 cm nebo 40 cm od okraje palety, v z\u00e1vislosti na zp\u016fsobu jejich ulo\u017een\u00ed. <\/p>\n\n\n\n

V p\u0159\u00edpad\u011b stroj\u016f a syst\u00e9m\u016f mus\u00ed konstruk\u010dn\u00ed odd\u011blen\u00ed poskytnout konkr\u00e9tn\u00ed \u00fadaje.<\/p>\n<\/div>\n\n\n\n

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Tento diagram z p\u0159\u00edlohy 4 kodexu \u010cVUT na stran\u011b 133 usnad\u0148uje pochopen\u00ed a ukazuje, jak m\u011b\u0159it.<\/p>\n<\/div>\n<\/div>\n\n\n\n

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\"CTU-Code-Page-133-Appendix-4-Weight-Distribution-Calculation-Rothschenk-Load-Security\n\t\t\t\n\t\t\t\t\n\t\t\t<\/svg>\n\t\t<\/button><\/figure>\n<\/figure>\n<\/div>\n<\/div>\n\n
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P\u0159\u00edklad v\u00fdpo\u010dtu z k\u00f3du \u010cVUT lze tak\u00e9 pou\u017e\u00edt jako \u0161ablonu pro v\u00fdpo\u010detn\u00ed tabulku. Sou\u010det v\u0161ech jednotliv\u00fdch v\u00fdpo\u010dt\u016f se vyd\u011bl\u00ed celkovou hmotnost\u00ed n\u00e1kladu. T\u00edm z\u00edsk\u00e1me vzd\u00e1lenost mezi celkov\u00fdm t\u011b\u017ei\u0161t\u011bm a koncovou st\u011bnou. Tato vzd\u00e1lenost pak mus\u00ed b\u00fdt v rozmez\u00ed 5 % nebo 10 % kontejneru. <\/p>\n<\/div>\n\n\n\n

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Klasick\u00fd blok p\u011bti europalet, kter\u00e9 v\u0161echny v\u00e1\u017e\u00ed stejn\u011b, lze vypo\u010d\u00edtat zjednodu\u0161en\u00fdm zp\u016fsobem.<\/p>\n\n\n\n

5 x 800 kg x 1,20 m<\/strong> = 4 800 kgm<\/p>\n<\/div>\n\n\n\n

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V\u00fdpo\u010det pro druh\u00fd blok p\u011bti by byl n\u00e1sleduj\u00edc\u00ed:<\/p>\n\n\n\n

5 x 800 kg x 3,60 m<\/strong> = 14 400 kgm<\/p>\n<\/div>\n\n\n\n

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\"Weight-distribution-second-block-of-five-redshank-load-securing\"\n\t\t\t\n\t\t\t\t\n\t\t\t<\/svg>\n\t\t<\/button><\/figure>\n<\/figure>\n<\/div>\n<\/div>\n\n
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T\u011b\u017ei\u0161t\u011b se pak vypo\u010d\u00edt\u00e1 takto:<\/p>\n\n\n\n

4 800 kgm + 14 400 kgm = 2,4 m_________________________________ 8 000 kg. <\/p>\n\n\n\n

Tuto polohu lze odvodit i \u010dist\u011b vizu\u00e1ln\u011b.<\/p>\n<\/div>\n\n\n\n

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Pokud se hmotnost palet v\u00fdrazn\u011b li\u0161\u00ed, mus\u00ed se ka\u017ed\u00e1 n\u00e1kladov\u00e1 jednotka po\u010d\u00edtat zvl\u00e1\u0161\u0165.<\/p>\n\n

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Pro tento fiktivn\u00ed p\u0159\u00edklad by v\u00fdpo\u010det vypadal n\u00e1sledovn\u011b:<\/p>\n\n\n\n

700kg x 0,40m = 280kgm 800kg x 1,20m = 960kgm 900kg x 2,00m = 1 800kgm1 000kg x 0,60m = 600kgm1 100kg x 1,60m = 1 760kgm_____________________________4 500kg 5 400kgm5 400kgm \/ 4 500kg = 1,20m<\/p>\n<\/div>\n\n\n\n

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Celkov\u00e9 t\u011b\u017ei\u0161t\u011b bloku p\u011bti je 1,20 m od \u010deln\u00ed st\u011bny, i kdy\u017e maj\u00ed zat\u011b\u017eovac\u00ed jednotky r\u016fznou hmotnost. Pokud maj\u00ed nosn\u00e9 prvky r\u016fzn\u00e9 rozm\u011bry, nemus\u00ed to b\u00fdt samoz\u0159ejm\u011b spr\u00e1vn\u011b. <\/p>\n\n

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Z uveden\u00fdch p\u0159\u00edklad\u016f je z\u0159ejm\u00e9, \u017ee v\u00fdpo\u010det celkov\u00e9ho t\u011b\u017ei\u0161t\u011b nen\u00ed \u017e\u00e1dn\u00e1 raketov\u00e1 v\u011bda. Na druhou stranu je obt\u00ed\u017en\u011bj\u0161\u00ed vytvo\u0159it z toho pl\u00e1n ulo\u017een\u00ed. <\/p>\n\n

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Ve firm\u00e1ch, kde k t\u00e9to situaci doch\u00e1z\u00ed pravideln\u011b, se vyplat\u00ed s trochou pe\u010dlivosti sestavit tabulku faktur tak, aby mohla slou\u017eit i jako pl\u00e1n ukl\u00e1d\u00e1n\u00ed. <\/p>\n\n\n\n

To usnad\u0148uje \u017eonglov\u00e1n\u00ed tam a zp\u011bt. Na obr\u00e1zku je p\u0159\u00edklad, jak by takov\u00e1 tabulka mohla vypadat. <\/p>\n<\/div>\n\n\n\n

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Kodex \u010cT\u00da stanov\u00ed p\u0159esn\u011bj\u0161\u00ed po\u017eadavky v odstavci 3.1.4 p\u0159\u00edlohy 7. Odchylka t\u011b\u017ei\u0161t\u011b by m\u011bla b\u00fdt zpravidla 5 % od st\u0159edu kontejneru. U 40stopov\u00e9ho kontejneru by to bylo +\/-30 cm mimo pod\u00e9ln\u00fd st\u0159ed a u 20stopov\u00e9ho kontejneru +\/- 15 cm. <\/p>\n\n

Pokud je t\u011b\u017ei\u0161t\u011b mimo specifikaci 10 %, m\u016f\u017eete je\u0161t\u011b zkontrolovat, zda je rozd\u011blen\u00ed 60\/40 \u00fasp\u011b\u0161n\u00e9. To znamen\u00e1, \u017ee 60 % hmotnosti n\u00e1kladu je v jedn\u00e9 polovin\u011b kontejneru a 40 % v druh\u00e9. P\u0159i pou\u017eit\u00ed tohoto pravidla 60\/40 je v\u0161ak t\u0159eba db\u00e1t na to, aby 60 % nebylo na p\u0159edn\u00ed st\u011bn\u011b, aby nedo\u0161lo k p\u0159ekro\u010den\u00ed zat\u00ed\u017een\u00ed hnac\u00ed n\u00e1pravy taha\u010de. To m\u016f\u017ee b\u00fdt v r\u016fzn\u00fdch zem\u00edch velmi n\u00e1kladn\u00e9. <\/p>\n\n

P\u0159\u00edpustn\u00e9 jsou v\u0161echny t\u0159i varianty, p\u0159i\u010dem\u017e pravidlo 5 % by m\u011blo b\u00fdt obecn\u011b up\u0159ednost\u0148ov\u00e1no. Pokud \u017e\u00e1dn\u00fd z t\u011bchto t\u0159\u00ed po\u017eadavk\u016f nen\u00ed \u00fasp\u011b\u0161n\u00fd, je t\u0159eba v\u017edy konzultovat odes\u00edlatele (p\u0159epravn\u00ed spole\u010dnost\/spedi\u010dn\u00ed agent). To m\u016f\u017ee b\u00fdt zejm\u00e9na p\u0159\u00edpad stroj\u016f a za\u0159\u00edzen\u00ed. <\/p>\n\n

Vy\u0161et\u0159ov\u00e1n\u00ed nehod kontejnerov\u00fdch lod\u00ed, nap\u0159\u00edklad ztracen\u00fdch kontejner\u016f na mo\u0159i, opakovan\u011b ukazuje, \u017ee nespr\u00e1vn\u00e9 upevn\u011bn\u00ed n\u00e1kladu nebo rozlo\u017een\u00ed n\u00e1kladu v kontejneru m\u016f\u017ee b\u00fdt jednou z p\u0159\u00ed\u010din, kter\u00e9 vedou k mnohem v\u011bt\u0161\u00edm \u0161kod\u00e1m, jako je dominov\u00fd efekt. Ztracen\u00fd kontejner plovouc\u00ed v bl\u00edzkosti hladiny je tak\u00e9 zna\u010dn\u00fdm nebezpe\u010d\u00edm pro b\u011b\u017enou lodn\u00ed dopravu, zejm\u00e9na pro n\u00e1mo\u0159n\u00edky na v\u00fdletn\u00edch lod\u00edch. <\/p>\n\n

Douf\u00e1m, \u017ee se mi poda\u0159ilo povzbudit z\u00fa\u010dastn\u011bn\u00e9\/posti\u017een\u00e9 osoby, aby se situac\u00ed zab\u00fdvaly a vypracovaly \u0159e\u0161en\u00ed specifick\u00e9 pro danou spole\u010dnost. Stoj\u00ed to za to, proto\u017ee reorganizace a p\u0159epracov\u00e1n\u00ed stoj\u00ed mnohem v\u00edce \u010dasu a pen\u011bz. <\/p>\n\n

V\u00e1\u0161, Sigurd Ehringer<\/p>\n\n

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<< P\u0159edchoz\u00ed \u010dl\u00e1nekD\u00edl 45: Jsou str\u00e1nky vzduchov\u00fd vak pou\u017e\u00edvan\u00e9 p\u0159\u00ed\u010dn\u011b a pod\u00e9ln\u011b ke sm\u011bru j\u00edzdy v souladu s p\u0159edpisy \u010cT\u00da?<\/a><\/p>\n<\/div>\n\n\n\n

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Dal\u0161\u00ed \u010dl\u00e1nek >>47. d\u00edl: Je nutn\u00e9 zajistit n\u00e1klad nav horn\u00ed \u010d\u00e1sti kontejneru?<\/a><\/p>\n<\/div>\n<\/div>\n\n

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Sigurd Ehringer<\/p>

\u2714 VDI-zertifizierter Ausbilder f\u00fcr Ladungssicherung\r\n\u2714 Fachbuch-Autor\r\n\u2714 8 Jahre Projektmanager\r\n\u2714 12 Jahre bei der Bundeswehr (Kompaniechef)\r\n\u2714 20 Jahre Vertriebserfahrung\r\n\u2714 seit 1996 Berater\/Ausbilder in der Logistik\r\n\u2714 44 Jahre Ausbilder\/Trainer in verschiedenen Bereichen —>\r\n\r\nIn einer Reihe von Fachbeitr\u00e4gen aus der Praxis, zu Themen rund um den Container und LKW, erhalten Sie Profiwissen aus erster Hand. Wie sichert man Ladung korrekt und was sind die Grundlagen der Ladungssicherung?\r\nErarbeitet und vorgestellt werden sie von Sigurd Ehringer, Inhaber von SE-LogCon<\/a>.<\/p><\/div><\/div><\/div>\n\n\n\n

<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

Rozlo\u017een\u00ed n\u00e1kladu v kontejnerech je v\u017edy p\u0159edm\u011btem diskus\u00ed. Na rozd\u00edl od star\u00fdch „Pokyn\u016f pro balen\u00ed CTU“ nen\u00ed Kodex CTU 2015 doporu\u010den\u00edm, ale z\u00e1vazn\u00fdm souborem pravidel obsahuj\u00edc\u00edm specifikace, kter\u00e9 je t\u0159eba dodr\u017eovat a kter\u00e9 lze tak\u00e9 kontrolovat. Jako p\u0159\u00edklad lze pou\u017e\u00edt sou\u010det mezer. Kontroln\u00ed pracovn\u00edk p\u0159epravn\u00ed spole\u010dnosti nebo p\u0159\u00edstavn\u00edho org\u00e1nu otev\u0159e kontejner, zm\u011b\u0159\u00ed vzd\u00e1lenost od zadn\u00edch […]<\/p>\n","protected":false},"author":1536,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[864,866,916],"tags":[],"class_list":["post-678620","post","type-post","status-publish","format-standard","hentry","category-cargo-blog-cs","category-fyzicka-stranka","category-kontejner"],"acf":[],"yoast_head":"\nBLOG: Rozlo\u017een\u00ed hmotnosti v kontejneru | 5 %? | 10%? | 60\/40 | Rothschenk<\/title>\n<meta name=\"description\" content=\"Jak\u00e9 rozlo\u017een\u00ed hmotnosti plat\u00ed? \u2714 P\u0159\u00edklady \u2714 P\u0159\u00edklady zat\u00ed\u017een\u00ed \u2714 Technick\u00fd \u010dl\u00e1nek \u2714 V\u00fdpo\u010det pl\u00e1nu zat\u00ed\u017een\u00ed \u2714 BLOG\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/rothschenk.de\/cs\/epizoda-46-rozdeleni-hmotnosti-podle-kodu-cvut-5-nebo-10-nebo-60-40\/\" \/>\n<meta property=\"og:locale\" content=\"cs_CZ\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"BLOG: Rozlo\u017een\u00ed hmotnosti v kontejneru | 5 %? 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