{"id":679368,"date":"2024-10-23T16:28:58","date_gmt":"2024-10-23T14:28:58","guid":{"rendered":"https:\/\/rothschenk.de\/epizoda-48-vypocet-vzduchovy-vak-podle-zbozi-co-je-spravne\/"},"modified":"2025-06-30T16:46:31","modified_gmt":"2025-06-30T14:46:31","slug":"epizoda-48-vypocet-vzduchovy-vak-podle-zbozi-co-je-spravne","status":"publish","type":"post","link":"https:\/\/rothschenk.de\/cz\/epizoda-48-vypocet-vzduchovy-vak-podle-zbozi-co-je-spravne\/","title":{"rendered":"Epizoda 48: V\u00fdpo\u010det vzduchov\u00fd vak podle zbo\u017e\u00ed – co je spr\u00e1vn\u011b?"},"content":{"rendered":"\n

Pou\u017eit\u00ed prokladov\u00fdch pytl\u016f v kontejnerech je b\u011b\u017enou metodou a nepostradatelnou sou\u010d\u00e1st\u00ed reperto\u00e1ru metod zaji\u0161t\u011bn\u00ed. Jedn\u00e1 se v\u0161ak o metodu, jej\u00ed\u017e \u00fa\u010dinnost je z\u0159ejm\u00e1, ale kter\u00e1 je tak\u00e9 spojena s riziky. Kodex CTU v\u011bnuje ukl\u00e1dac\u00edm pol\u0161t\u00e1\u0159\u016fm celou kapitolu v dodatku 7 p\u0159\u00edlohy 4 a je nabit\u00fd vzorci, kter\u00e9 se na prvn\u00ed pohled zdaj\u00ed b\u00fdt pro b\u011b\u017en\u00e9ho odes\u00edlatele\/odes\u00edlatele ohromuj\u00edc\u00ed. Zd\u00e1 se proto vhodn\u00e9 osv\u011btlit toto t\u00e9ma a vysv\u011btlit logiku v n\u011bm obsa\u017eenou.Obecn\u011b plat\u00ed, \u017ee vzduchov\u00fd vak slou\u017e\u00ed k uzav\u0159en\u00ed st\u00e1vaj\u00edc\u00edch mezer mezi n\u00e1kladov\u00fdmi jednotkami v kontejneru a k nep\u0159eru\u0161ovan\u00e9mu p\u0159enosu v\u00fdsledn\u00fdch sil zrychlen\u00ed n\u00e1kladu na st\u011bny kontejneru. <\/p>\n\n

Zde jsou pops\u00e1ny dva p\u0159\u00edstupy:<\/strong>1. Jak velk\u00fd mus\u00ed b\u00fdt vzduchov\u00fd vak, aby zabr\u00e1nil pohybu b\u0159emene o zn\u00e1m\u00e9 hmotnosti p\u0159i definovan\u00fdch zrychlen\u00edch a sou\u010dinitel\u00edch t\u0159en\u00ed?2. Jak\u00e9 zat\u011b\u017eovac\u00ed s\u00edly m\u016f\u017ee absorbovat vzduchov\u00fd vak se zn\u00e1m\u00fdmi rozm\u011bry a plnic\u00edm tlakem?Odpov\u00eddaj\u00edc\u00ed vzorce pro ob\u011b ot\u00e1zky lze nal\u00e9zt v p\u0159edpisu \u010cVUT.<\/p>\n\n

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Vzorce vpravo slou\u017e\u00ed k v\u00fdpo\u010dtu n\u00e1bojov\u00e9 s\u00edly, kter\u00e1 vznik\u00e1 p\u0159i ur\u010dit\u00fdch zrychlen\u00edch a koeficientech t\u0159en\u00ed.<\/p>\n\n\n\n

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\"vzduchový\n\t\t\t\n\t\t\t\t\n\t\t\t<\/svg>\n\t\t<\/button><\/figure>\n<\/figure>\n<\/div>\n<\/div>\n\n
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N\u00e1sleduj\u00edc\u00ed \u00favahy op\u011bt vych\u00e1zej\u00ed z klasick\u00e9ho bloku p\u011bti europalet.U pod\u00e9ln\u011b stoj\u00edc\u00edch jednotek p\u0159edpokl\u00e1d\u00e1me hmotnost zat\u00ed\u017een\u00ed 2 x 900 kg a u p\u0159\u00ed\u010dn\u011b stoj\u00edc\u00edch jednotek 3 x 800 kg. V z\u00e1vislosti na \u00fahlu odvalov\u00e1n\u00ed je t\u0159eba po\u010d\u00edtat s 1 800 kg nebo 2 400 kg. P\u0159edpis CTU stanov\u00ed, \u017ee v ka\u017ed\u00e9m p\u0159\u00edpad\u011b mus\u00ed b\u00fdt pou\u017eita vy\u0161\u0161\u00ed hmotnost n\u00e1kladu.P\u0159edpokl\u00e1d\u00e1me tyto dal\u0161\u00ed faktory:Xy = 0,8g Zrychlen\u00ed p\u0159i p\u0159evalov\u00e1n\u00edCz = 0,2 Zrychlen\u00ed p\u0159i n\u00e1klonu\u03bc = 0,3 Koeficient t\u0159en\u00ed na podlaze kontejneruSF = 0,75 Bezpe\u010dnostn\u00ed faktor pro polstrov\u00e1n\u00ed pro 1x pou\u017eit\u00edHmotnost = 2,4 t neboHmotnost = 2400 kgZrychlen\u00ed p\u016fsoben\u00edm gravitace = 9,81 m\/s2 ~ 10 m\/s2<\/p>\n\n\n\n

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\"Kreslení-vzduchový\n\t\t\t\n\t\t\t\t\n\t\t\t<\/svg>\n\t\t<\/button><\/figure>\n<\/figure>\n<\/div>\n<\/div>\n\n

V\u00fdpo\u010det lze tak\u00e9 zjednodu\u0161it pro odborn\u00edky, kte\u0159\u00ed jsou l\u00e9pe obezn\u00e1meni s jednotkou „daN“. To m\u00e1 uk\u00e1zat p\u0159\u00edklad v\u00fdpo\u010dtu. Prvn\u00ed \u0159\u00e1dek po\u010d\u00edt\u00e1 s tunami a druh\u00fd s kilogramy. Pro p\u0159epo\u010det z kN na daN je t\u0159eba v\u00fdsledek nejprve vyn\u00e1sobit 1 000 a pot\u00e9 vyd\u011blit deseti. Pokud vezmete hmotnost b\u0159emene v kg a vypo\u010dtete t\u00edhov\u00e9 zrychlen\u00ed jako 1, z\u00edsk\u00e1te v\u00fdsledek v daN v jednom v\u00fdpo\u010dtu. <\/p>\n\n

\"Vzorec-vzduchový\n\t\t\t\n\t\t\t\t\n\t\t\t<\/svg>\n\t\t<\/button><\/figure>\n\n

V\u00fdsledek: Pol\u0161t\u00e1\u0159 mus\u00ed b\u00fdt schopen absorbovat zat\u011b\u017eovac\u00ed s\u00edlu 1812daN.<\/p>\n\n

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V dodatku 7, p\u0159\u00edloze 4, kapitole 4.3 je vypo\u010d\u00edt\u00e1na s\u00edla, kterou m\u016f\u017ee vzduchov\u00fd vak absorbovat v z\u00e1vislosti na tlaku p\u0159i roztr\u017een\u00ed. Vzorec je t\u0159eba p\u0159euspo\u0159\u00e1dat, aby se ur\u010dila sty\u010dn\u00e1 plocha n\u00e1razn\u00edku: <\/p>\n\n\n\n

\"Vzorec-vzduchový<\/figure>\n\n\n\n

Pokud pou\u017eijeme s\u00edlu zat\u00ed\u017een\u00ed z v\u00fd\u0161e uveden\u00e9ho p\u0159\u00edkladu, mus\u00ed m\u00edt str\u00e1nka vzduchov\u00fd vak plochu 0,45 m2<\/strong>, aby tuto s\u00edlu absorbovala.<\/p>\n<\/div>\n\n\n\n

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\"Vzorec-vzduchový\n\t\t\t\n\t\t\t\t\n\t\t\t<\/svg>\n\t\t<\/button><\/figure>\n<\/figure>\n\n\n\n
\"Load-force-formula-vzduchový\n\t\t\t\n\t\t\t\t\n\t\t\t<\/svg>\n\t\t<\/button><\/figure>\n<\/div>\n<\/div>\n\n
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Abychom mohli pokra\u010dovat v pr\u00e1ci s p\u0159\u00edkladem, p\u0159edstavme si celou v\u011bc shora.Vnit\u0159n\u00ed \u0161\u00ed\u0159ka kontejneru = 2,34 mEuro paleta: 0,80 x 1,20 m\u010cist\u011b matematicky to znamen\u00e1 n\u00e1sleduj\u00edc\u00ed \u0161\u00ed\u0159ku mezery:2,34 m – 0,80 m – 1,20 m = 0,34 ma d\u00e9lku mezery 2,40 m.P\u0159edpokl\u00e1d\u00e1me-li, \u017ee v\u00fd\u0161ka palet je 1,60 m, vznikne maxim\u00e1ln\u00ed plocha polstrov\u00e1n\u00ed: 1,60 m x 2,40 m = 3,84 m2<\/strong>.<\/p>\n<\/div>\n\n\n\n

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\"Pět<\/figure>\n<\/div>\n<\/div>\n\n
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Pokud p\u0159edpokl\u00e1d\u00e1me, \u017ee podlo\u017eka by m\u011bla nejen absorbovat s\u00edlu zat\u00ed\u017een\u00ed, ale tak\u00e9 zajistit cel\u00fd n\u00e1klad proti zkroucen\u00ed\/posunut\u00ed, pak by d\u00e9lka podlo\u017eky 2,00 m byla dostate\u010dn\u00e1. Za p\u0159edpokladu, \u017ee palety jsou stabiln\u00ed i v\u00fd\u0161kov\u011b, by se v\u00fd\u0161ka podlo\u017eky mohla sn\u00ed\u017eit na 1,40 m.\u00da\u010dinn\u00e1 plocha podlo\u017eky 2,00 m x 1,40 m = 2,80 m2.<\/strong> <\/p>\n<\/div>\n\n\n\n

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\"Pět<\/figure>\n<\/div>\n<\/div>\n\n

Porovn\u00e1me-li nyn\u00ed oba vypo\u010dten\u00e9 v\u00fdsledky, tj. 0,45 m2 po\u017eadovan\u00e9 z hmotnosti n\u00e1kladu, s plochou vypl\u00fdvaj\u00edc\u00ed z rozm\u011br\u016f n\u00e1kladu, tj. 2,80 m2, z\u00edsk\u00e1me \u0161estin\u00e1sobek bezpe\u010dnostn\u00edho faktoru.<\/p>\n\n

Z vypo\u010dten\u00fdch \u00fadaj\u016f vypl\u00fdv\u00e1, \u017ee pol\u0161t\u00e1\u0159 dimenzovan\u00fd podle zat\u00ed\u017een\u00ed m\u016f\u017ee obecn\u011b absorbovat podstatn\u011b v\u011bt\u0161\u00ed zat\u011b\u017eovac\u00ed s\u00edlu, ne\u017e je ve skute\u010dnosti pot\u0159eba. To tak\u00e9 vede k z\u00e1v\u011bru, \u017ee vysok\u00fd plnic\u00ed tlak nen\u00ed nutn\u00fd. Pou\u017eit\u00ed vak\u016f s propl\u00e1stky vy\u017eaduje hodn\u011b vzduchu, ale mal\u00fd tlak. Pln\u011bn\u00ed pomoc\u00ed syst\u00e9mu stla\u010den\u00e9ho vzduchu trv\u00e1 d\u00e9le ne\u017e pomoc\u00ed dmychadla. Za p\u0159edpokladu, \u017ee nedojde k dal\u0161\u00edm technick\u00fdm chyb\u00e1m, jste v\u017edy na bezpe\u010dn\u00e9 stran\u011b. Samoz\u0159ejm\u011b je v\u017edy nutn\u00e9 konzultovat s dodavatelem vzduchov\u00fd vak a vy\u017e\u00e1dat si konkr\u00e9tn\u00ed \u00fadaje o manipulaci.V\u00fd\u0161e uveden\u00fd popis tak\u00e9 ukazuje, \u017ee navzdory mnoha vzorc\u016fm nen\u00ed k\u00f3d \u010cVUT tak slo\u017eit\u00fd, jak se na prvn\u00ed pohled zd\u00e1. Nebojte se proto pod\u00edvat se na pravidla a p\u0159edpisy bl\u00ed\u017ee. <\/p>\n\n

V\u00e1\u0161, Sigurd Ehringer<\/strong><\/p>\n\n

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<< P\u0159edchoz\u00ed \u010dl\u00e1nekD\u00edl 47: Je nutn\u00e9 zaji\u0161\u0165ovat n\u00e1klad v kontejnerech sm\u011brem nahoru?<\/a><\/p>\n<\/div>\n\n\n\n

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K dal\u0161\u00edmu p\u0159\u00edsp\u011bvku >><\/p>\n<\/div>\n<\/div>\n\n

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\"\"<\/figure>\n<\/div>\n\n\n\n

Sigurd Ehringer<\/p>

\u2714 VDI-zertifizierter Ausbilder f\u00fcr Ladungssicherung\r\n\u2714 Fachbuch-Autor\r\n\u2714 8 Jahre Projektmanager\r\n\u2714 12 Jahre bei der Bundeswehr (Kompaniechef)\r\n\u2714 20 Jahre Vertriebserfahrung\r\n\u2714 seit 1996 Berater\/Ausbilder in der Logistik\r\n\u2714 44 Jahre Ausbilder\/Trainer in verschiedenen Bereichen —>\r\n\r\nIn einer Reihe von Fachbeitr\u00e4gen aus der Praxis, zu Themen rund um den Container und LKW, erhalten Sie Profiwissen aus erster Hand. Wie sichert man Ladung korrekt und was sind die Grundlagen der Ladungssicherung?\r\nErarbeitet und vorgestellt werden sie von Sigurd Ehringer, Inhaber von SE-LogCon<\/a>.<\/p><\/div><\/div><\/div>\n\n\n\n

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<\/p>\n","protected":false},"excerpt":{"rendered":"

Pou\u017eit\u00ed prokladov\u00fdch pytl\u016f v kontejnerech je b\u011b\u017enou metodou a nepostradatelnou sou\u010d\u00e1st\u00ed reperto\u00e1ru metod zaji\u0161t\u011bn\u00ed. Jedn\u00e1 se v\u0161ak o metodu, jej\u00ed\u017e \u00fa\u010dinnost je z\u0159ejm\u00e1, ale kter\u00e1 je tak\u00e9 spojena s riziky. Kodex CTU v\u011bnuje ukl\u00e1dac\u00edm pol\u0161t\u00e1\u0159\u016fm celou kapitolu v dodatku 7 p\u0159\u00edlohy 4 a je nabit\u00fd vzorci, kter\u00e9 se na prvn\u00ed pohled zdaj\u00ed b\u00fdt pro b\u011b\u017en\u00e9ho […]<\/p>\n","protected":false},"author":1536,"featured_media":679377,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[864,866,916],"tags":[],"class_list":["post-679368","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cargo-blog-cs","category-fyzicka-stranka","category-kontejner"],"acf":[],"yoast_head":"\nBLOG: V\u00fdpo\u010det vzduchov\u00fd vak podle zbo\u017e\u00ed - co je spr\u00e1vn\u011b?<\/title>\n<meta name=\"description\" content=\"Co je povoleno a v souladu s kodexem \u010cVUT? \u2714 V\u00fdpo\u010det \u2714 Spr\u00e1vn\u00e1 velikost \u2714 Technick\u00fd \u010dl\u00e1nek s p\u0159\u00edklady v\u00fdpo\u010dtu \u2714 BLOG Sigurda Ehringera\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/rothschenk.de\/cs\/epizoda-48-vypocet-vzduchovy-vak-podle-zbozi-co-je-spravne\/\" \/>\n<meta property=\"og:locale\" content=\"cs_CZ\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"BLOG: V\u00fdpo\u010det vzduchov\u00fd vak podle zbo\u017e\u00ed - co je spr\u00e1vn\u011b?\" \/>\n<meta property=\"og:description\" content=\"Co je povoleno a v souladu s kodexem \u010cVUT? 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