{"id":680306,"date":"2023-11-06T14:15:49","date_gmt":"2023-11-06T13:15:49","guid":{"rendered":"https:\/\/rothschenk.de\/epizoda-37-rozlozeni-nakladu-na-nakladnich-vozidlech-jak-spravne-vypocitat-hodnoty\/"},"modified":"2025-06-30T16:59:46","modified_gmt":"2025-06-30T14:59:46","slug":"epizoda-37-rozlozeni-nakladu-na-nakladnich-vozidlech-jak-spravne-vypocitat-hodnoty","status":"publish","type":"post","link":"https:\/\/rothschenk.de\/cz\/epizoda-37-rozlozeni-nakladu-na-nakladnich-vozidlech-jak-spravne-vypocitat-hodnoty\/","title":{"rendered":"Epizoda 37: Rozlo\u017een\u00ed n\u00e1kladu na n\u00e1kladn\u00edch vozidlech – jak spr\u00e1vn\u011b vypo\u010d\u00edtat hodnoty?"},"content":{"rendered":"\n

Rozlo\u017een\u00ed n\u00e1kladu na n\u00e1kladn\u00edch vozidlech opakovan\u011b p\u0159edstavuje pro \u0159idi\u010de i naklada\u010de velkou v\u00fdzvu, ke kter\u00e9 se \u010dasto p\u0159istupuje s „polovi\u010dn\u00edmi znalostmi“.<\/p>\n\n

Pokud m\u00e1te z\u00e1kladn\u00ed znalosti fyziky, lze tento probl\u00e9m vy\u0159e\u0161it pom\u011brn\u011b snadno.<\/p>\n\n

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Vizualizace rozlo\u017een\u00ed zat\u00ed\u017een\u00ed<\/h2>\n\n
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Nejjednodu\u0161\u0161\u00ed je p\u0159edstavit si, \u017ee n\u00e1kladn\u00ed automobil stoj\u00ed sv\u00fdmi n\u00e1pravami na v\u00e1ze.<\/p>\n\n\n\n

Pokud je rozlo\u017een\u00ed zat\u00ed\u017een\u00ed spr\u00e1vn\u00e9, je ru\u010di\u010dka stupnice na nule nebo ve st\u0159edu.<\/p>\n<\/div>\n\n\n\n

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Pokud by byla p\u0159edn\u00ed n\u00e1prava p\u0159et\u00ed\u017een\u00e1, lev\u00e1 p\u00e1nev by se sn\u00ed\u017eila a prav\u00e1 zvedla. To by byl jasn\u00fd d\u016fsledek nespr\u00e1vn\u00e9ho rozlo\u017een\u00ed zat\u00ed\u017een\u00ed. <\/p>\n\n\n\n

Cel\u00e1 v\u011bc by se samoz\u0159ejm\u011b obr\u00e1tila, kdyby byla zadn\u00ed n\u00e1prava p\u0159et\u00ed\u017een\u00e1.<\/p>\n<\/div>\n<\/div>\n\n

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Tento z\u00e1kladn\u00ed princip aplikovan\u00fd na n\u00e1v\u011bs lze zjednodu\u0161it p\u0159id\u00e1n\u00edm dal\u0161\u00ed v\u00e1hy na levou v\u00e1hovou misku, na kter\u00e9 spo\u010d\u00edv\u00e1 \u0159\u00eddic\u00ed a hnac\u00ed n\u00e1prava.<\/p>\n<\/div>\n<\/div>\n\n

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V p\u0159edpisech „Vozidla DGUV70“ n\u011bmeck\u00e9ho \u00farazov\u00e9ho poji\u0161t\u011bn\u00ed jsou v koment\u00e1\u0159i uvedeny n\u00e1sleduj\u00edc\u00ed okrajov\u00e9 podm\u00ednky:K \u00a7 37 odst. 1: Po\u017eadavek na dodr\u017een\u00ed p\u0159\u00edpustn\u00fdch hodnot zat\u00ed\u017een\u00ed na n\u00e1pravu je spln\u011bn, pokud: <\/p>\n\n\n\n

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  1. P\u0159\u00edpustn\u00e9 zat\u00ed\u017een\u00ed p\u0159edn\u00ed n\u00e1pravy <\/strong>nen\u00ed p\u0159ekro\u010deno.<\/li>\n\n\n\n
  2. P\u0159\u00edpustn\u00e9 zat\u00ed\u017een\u00ed zadn\u00ed n\u00e1pravy <\/strong>nen\u00ed p\u0159ekro\u010deno a<\/li>\n\n\n\n
  3. Minim\u00e1ln\u00ed zat\u00ed\u017een\u00ed \u0159\u00edzen\u00e9 n\u00e1<\/strong> pravy je nejm\u00e9n\u011b 20 % momentov\u00e9 hmotnosti vozidla (neplat\u00ed pro n\u00e1v\u011bsy).<\/li>\n<\/ol>\n\n\n\n

    Pokud rychlost j\u00edzdy nep\u0159ekro\u010d\u00ed 25 km\/h, m\u016f\u017ee b\u00fdt minim\u00e1ln\u00ed zat\u00ed\u017een\u00ed \u0159\u00edzen\u00e9 n\u00e1pravy sn\u00ed\u017eeno na 10 % momentov\u00e9 hmotnosti vozidla.<\/p>\n<\/div>\n<\/div>\n\n

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    Pl\u00e1n rozlo\u017een\u00ed z\u00e1t\u011b\u017ee<\/h3>\n\n

    Hlavn\u00edm z\u00e1kladem pro \u00favahy je pl\u00e1n rozlo\u017een\u00ed z\u00e1t\u011b\u017ee, kter\u00fd je specifick\u00fd pro ka\u017ed\u00fd typ vozidla. P\u0159edlohou pro obr\u00e1zek je program BG pro v\u00fdpo\u010det pl\u00e1n\u016f rozlo\u017een\u00ed z\u00e1t\u011b\u017ee. Obr\u00e1zek byl upraven pro \u00fa\u010dely vizualizace.(Pl\u00e1n rozd\u011blen\u00ed n\u00e1kladu LVP 4.1 + Z\u00e1kladn\u00ed z\u00e1sady zaji\u0161t\u011bn\u00ed n\u00e1kladu – BG Verkehr (bg-verkehr.de)<\/a>)<\/p>\n\n

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    Celkov\u00e9 t\u011b\u017ei\u0161t\u011b n\u00e1kladu mus\u00ed b\u00fdt v\u017edy pod modrou \u010darou. N\u00e1klad o hmotnosti max. 2 000 kg m\u016f\u017ee b\u00fdt um\u00edst\u011bn kdekoli na lo\u017en\u00e9 plo\u0161e. Pokud v\u0161ak n\u00e1klad v\u00e1\u017e\u00ed 9 000 kg, mus\u00ed b\u00fdt t\u011b\u017ei\u0161t\u011b ve vzd\u00e1lenosti 3,40 m od p\u0159ep\u00e1\u017eky. \u010c\u00edm t\u011b\u017e\u0161\u00ed je n\u00e1klad, t\u00edm men\u0161\u00ed je voln\u00fd prostor. <\/p>\n\n

    V diagramu jsou tak\u00e9 d\u016fle\u017eit\u00e9 dv\u011b grafick\u00e9 osy. Osa X ozna\u010duje d\u00e9lku lo\u017en\u00e9 plochy a osa Y u\u017eite\u010dn\u00e9 zat\u00ed\u017een\u00ed. <\/p>\n\n

    P\u0159\u00edklad: P\u0159\u00edklad: Pokud cel\u00e9 b\u0159emeno v\u00e1\u017e\u00ed 7 000 kg, p\u0159ejd\u011bte na Y=7to a pak doleva na modrou \u010d\u00e1ru.Je dvakr\u00e1t protnuta, tak\u017ee t\u011b\u017ei\u0161t\u011b b\u0159emene m\u016f\u017ee b\u00fdt ve vzd\u00e1lenosti 3 m a\u017e 5 m od koncov\u00e9 st\u011bny. <\/p>\n\n

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    Z\u00e1kon p\u00e1kov\u00e9ho efektu<\/h2>\n\n

    Existuje v\u0161ak i jin\u00fd zp\u016fsob ur\u010den\u00ed t\u011b\u017ei\u0161t\u011b. K tomu si mus\u00edte vzpomenout na z\u00e1kon p\u00e1ky <\/strong>. S\u00edla (hmotnost b\u0159emene) vyn\u00e1soben\u00e1 d\u00e9lkou p\u00e1ky (vzd\u00e1lenost\u00ed od \u010deln\u00ed st\u011bny k t\u011b\u017ei\u0161ti n\u00e1kladov\u00e9 jednotky) d\u00e1v\u00e1 moment. Na stejn\u00e9m principu pracuje momentov\u00fd kl\u00ed\u010d. V tomto p\u0159\u00edpad\u011b v\u0161ak d\u00e9lka p\u00e1ky z\u016fst\u00e1v\u00e1 stejn\u00e1 a s\u00edlu lze nastavit. <\/p>\n\n

    P\u0159i pou\u017eit\u00ed t\u00e9to metody je nutn\u00e9 zn\u00e1t polohu t\u011b\u017ei\u0161t\u011b <\/strong>b\u0159emene. Zejm\u00e9na v p\u0159\u00edpad\u011b stroj\u016f a syst\u00e9m\u016f konstruk\u010dn\u00ed odd\u011blen\u00ed \u010dasto neozna\u010d\u00ed polohu t\u011b\u017ei\u0161t\u011b nebo alespo\u0148 neposkytne v\u00fdkres, kter\u00fd by jeho polohu zn\u00e1zor\u0148oval. Tato informace je z\u00e1sadn\u00ed pro spr\u00e1vn\u00e9 zat\u00ed\u017een\u00ed a zaji\u0161t\u011bn\u00ed b\u0159emene. <\/p>\n\n

    N\u00e1sleduje fiktivn\u00ed p\u0159\u00edklad, jak lze ur\u010dit t\u011b\u017ei\u0161t\u011b pro podobn\u00e9 n\u00e1kladov\u00e9 jednotky.<\/p>\n\n

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    U podobn\u00fdch n\u00e1klad\u016f, jako jsou velk\u00e9 pytle, oktabiny, IBC nebo palety s n\u00e1poji, se t\u011b\u017ei\u0161t\u011b s ka\u017edou dal\u0161\u00ed \u0159adou n\u00e1klad\u016f posouv\u00e1 d\u00e1le dozadu. Pro tuto \u00favahu nemus\u00ed b\u00fdt nutn\u011b zn\u00e1ma p\u0159esn\u00e1 hmotnost. <\/p>\n\n

    Na konci nakl\u00e1dky mus\u00ed \u0159idi\u010d a naklada\u010d v\u011bd\u011bt, zda je poloha celkov\u00e9ho t\u011b\u017ei\u0161t\u011b (zelen\u00e1 \u0161ipka) p\u0159\u00edpustn\u00e1, nebo ne. Pokud by tato poloha nebyla p\u0159\u00edpustn\u00e1, muselo by se znovu nalo\u017eit, vylo\u017eit a znovu nalo\u017eit. <\/p>\n\n

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    Matematick\u00e9 \u0159e\u0161en\u00ed p\u0159\u00edpadov\u00e9 studie<\/h3>\n\n

    Probl\u00e9m lze samoz\u0159ejm\u011b \u0159e\u0161it i matematicky. Nen\u00ed to obt\u00ed\u017en\u00e9, ale je to t\u011b\u017ek\u00e1 pr\u00e1ce. <\/p>\n\n

    Vezm\u011bte hmotnost (v kg) prvn\u00edho b\u0159emene a vyn\u00e1sobte ji vzd\u00e1lenost\u00ed (v m) mezi t\u011b\u017ei\u0161t\u011bm a p\u0159edn\u00ed st\u011bnou. Pokud jsou jednotky zat\u00ed\u017een\u00ed stejn\u00e9ho typu, lze pou\u017e\u00edt i celou \u0159adu zat\u00ed\u017een\u00ed. <\/p>\n\n

    Druh\u00e9 zat\u00ed\u017een\u00ed vyn\u00e1soben\u00e9 novou vzd\u00e1lenost\u00ed t\u011b\u017ei\u0161t\u011b se pak p\u0159i\u010dte k prvn\u00edmu v\u00fdsledku a tak d\u00e1le, dokud nejsou vypo\u010dteny v\u0161echny jednotky zat\u00ed\u017een\u00ed.<\/p>\n\n

    Celkov\u00fd v\u00fdsledek se vyd\u011bl\u00ed celkovou hmotnost\u00ed n\u00e1kladu.<\/p>\n\n

    V\u00fdsledkem je vzd\u00e1lenost mezi celkov\u00fdm t\u011b\u017ei\u0161t\u011bm b\u0159emene a \u010deln\u00ed st\u011bnou.<\/p>\n\n

    U standardn\u00edho n\u00e1v\u011bsu s maxim\u00e1ln\u00edm u\u017eite\u010dn\u00fdm zat\u00ed\u017een\u00edm mus\u00ed b\u00fdt tato vzd\u00e1lenost mezi 6,80 a 7,2.<\/p>\n\n

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    Ti z na\u0161ich \u010dten\u00e1\u0159\u016f, kte\u0159\u00ed jsou s Excelem dostate\u010dn\u011b zdatn\u00ed, si mohou pr\u00e1ci s v\u00fdpo\u010dty usnadnit. Mohou si vytvo\u0159it tabulku, kter\u00e1 jim po zad\u00e1n\u00ed \u00fadaj\u016f poskytne v\u00fdsledek. <\/p>\n\n

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    Z\u00e1v\u011br<\/h2>\n\n

    S t\u011bmito z\u00e1kladn\u00edmi znalostmi by m\u011blo b\u00fdt mo\u017en\u00e9 spr\u00e1vn\u011b ulo\u017eit n\u00e1klad do takov\u00e9 m\u00edry, aby nedo\u0161lo k poru\u0161en\u00ed bezpe\u010dnosti provozu a dopravy.<\/p>\n\n

    V\u017edy je t\u0159eba m\u00edt na pam\u011bti, \u017ee krom\u011b spr\u00e1vn\u00edho deliktu m\u016f\u017ee doj\u00edt i k trestn\u00e9mu \u010dinu. Konkr\u00e9tn\u011b v p\u0159\u00edpad\u011b, \u017ee nespr\u00e1vn\u011b nalo\u017een\u00e9 vozidlo m\u00e1 za n\u00e1sledek dopravn\u00ed nehodu se zran\u011bn\u00edm, usmrcen\u00edm osob nebo velkou \u0161kodou na majetku. <\/p>\n\n

    V\u0161ichni se tomu chceme vyhnout, proto\u017ee jako \u00fa\u010dastn\u00edci silni\u010dn\u00edho provozu m\u016f\u017eeme b\u00fdt tak\u00e9 kdykoli posti\u017eeni.<\/p>\n\n

    V\u00e1\u0161, Sigurd Ehringer<\/p>\n\n

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    << P\u0159edchoz\u00ed \u010dl\u00e1nekEpisode 36: Code XL – Load on the front wall – What needs to be considered?<\/a><\/p>\n<\/div>\n\n\n\n

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    K dal\u0161\u00edmu p\u0159\u00edsp\u011bvku >> Epizoda 38: Jak funguje protiskluzov\u00e1 podlo\u017eka? – \u010c\u00e1st 1: Princip fungov\u00e1n\u00ed <\/a><\/p>\n<\/div>\n<\/div>\n\n

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    Sigurd Ehringer<\/p>

    \u2714 VDI-zertifizierter Ausbilder f\u00fcr Ladungssicherung\r\n\u2714 Fachbuch-Autor\r\n\u2714 8 Jahre Projektmanager\r\n\u2714 12 Jahre bei der Bundeswehr (Kompaniechef)\r\n\u2714 20 Jahre Vertriebserfahrung\r\n\u2714 seit 1996 Berater\/Ausbilder in der Logistik\r\n\u2714 44 Jahre Ausbilder\/Trainer in verschiedenen Bereichen —>\r\n\r\nIn einer Reihe von Fachbeitr\u00e4gen aus der Praxis, zu Themen rund um den Container und LKW, erhalten Sie Profiwissen aus erster Hand. Wie sichert man Ladung korrekt und was sind die Grundlagen der Ladungssicherung?\r\nErarbeitet und vorgestellt werden sie von Sigurd Ehringer, Inhaber von SE-LogCon<\/a>.<\/p><\/div><\/div><\/div>\n\n\n\n

    <\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

    Rozlo\u017een\u00ed n\u00e1kladu na n\u00e1kladn\u00edch vozidlech opakovan\u011b p\u0159edstavuje pro \u0159idi\u010de i naklada\u010de velkou v\u00fdzvu, ke kter\u00e9 se \u010dasto p\u0159istupuje s „polovi\u010dn\u00edmi znalostmi“. Pokud m\u00e1te z\u00e1kladn\u00ed znalosti fyziky, lze tento probl\u00e9m vy\u0159e\u0161it pom\u011brn\u011b snadno. Vizualizace rozlo\u017een\u00ed zat\u00ed\u017een\u00ed Nejjednodu\u0161\u0161\u00ed je p\u0159edstavit si, \u017ee n\u00e1kladn\u00ed automobil stoj\u00ed sv\u00fdmi n\u00e1pravami na v\u00e1ze. Pokud je rozlo\u017een\u00ed zat\u00ed\u017een\u00ed spr\u00e1vn\u00e9, je ru\u010di\u010dka stupnice […]<\/p>\n","protected":false},"author":1536,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[864,866,865],"tags":[],"class_list":["post-680306","post","type-post","status-publish","format-standard","hentry","category-cargo-blog-cs","category-fyzicka-stranka","category-lorry"],"acf":[],"yoast_head":"\nRozlo\u017een\u00ed n\u00e1kladu na n\u00e1kladn\u00edch vozidlech | V\u00fdpo\u010dty | P\u0159\u00edklady - Rothschenk<\/title>\n<meta name=\"description\" content=\"Jak\u00e1 z\u00e1t\u011b\u017e vznik\u00e1? \u2714 Co je t\u0159eba vz\u00edt v \u00favahu p\u0159i nakl\u00e1d\u00e1n\u00ed? \u2714 K\u00f3d XL \u2714 B\u011b\u017en\u00e9 chyby \u2714 Po\u0161kozen\u00ed \u2714 Praktick\u00e9 p\u0159\u00edklady + \u0159e\u0161en\u00ed\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/rothschenk.de\/cz\/epizoda-37-rozlozeni-nakladu-na-nakladnich-vozidlech-jak-spravne-vypocitat-hodnoty\/\" \/>\n<meta property=\"og:locale\" content=\"cs_CZ\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Rozlo\u017een\u00ed n\u00e1kladu na n\u00e1kladn\u00edch vozidlech | V\u00fdpo\u010dty | P\u0159\u00edklady - Rothschenk\" \/>\n<meta property=\"og:description\" content=\"Jak\u00e1 z\u00e1t\u011b\u017e vznik\u00e1? 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