{"id":191876,"date":"2022-09-21T14:01:35","date_gmt":"2022-09-21T12:01:35","guid":{"rendered":"https:\/\/rothschenk.de\/episode-21-dunnage-bags-load-securing-part-2\/"},"modified":"2025-06-30T16:55:38","modified_gmt":"2025-06-30T14:55:38","slug":"episode-21-dunnage-bags-load-securing-part-2","status":"publish","type":"post","link":"https:\/\/rothschenk.de\/en\/episode-21-dunnage-bags-load-securing-part-2\/","title":{"rendered":"Episode 21: Dunnage bags load securing – Part 2"},"content":{"rendered":"\n

Why are there no problems in most cases, even though hardly anyone does the math? <\/p>\n\n

This can be proven on the basis of calculations. Provided that, as described in Part 1, no technical errors are made. <\/p>\n\n

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As a basic principle, the securing force exerted by the pad<\/a> must be at least as great as the force exerted by the load, and the load must not move.<\/p>\n<\/div>\n<\/div>\n\n

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Case studies<\/h2>\n\n

What would these barrel pallets do at a rolling angle of 37\u00ba?<\/p>\n\n

They would naturally slip or tip over. A rolling period of up to 2-3 times per minute is not unusual. The roll angle of 38\u00ba would correspond to the maximum acceleration of 0.8 g transverse to the direction of travel. <\/p>\n\n

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Let’s take the classic block of five Euro pallets as an example, as described in Part 1.<\/p>\n\n

The load units weigh 900 kg each and are 1.60 m high. The side length of the two blocks is 2.40 m each. <\/p>\n\n

The question now is, how large must the dunnage bag be so that the force from the load is compensated by 80% of the cushioning area?<\/p>\n\n

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Calculate the upholstery area:<\/strong><\/p>\n\n\n\n

Side length:<\/em>2.40 m x 0.8 = 1.92 m<\/p>\n\n\n\n

Height:<\/em>1.60 m x 0.8 = 1.28 m<\/p>\n\n\n\n

Gap width:<\/em>0.34 m<\/p>\n\n\n\n

The width of the gap between the loading units results from the internal width of the container of 2.34 m, minus the pallet dimensions of 1.20 m + 0.80 m, i.e. 0.34 m.<\/p>\n<\/div>\n<\/div>\n\n

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Formula for the effective area of a baffle plate<\/h2>\n\n
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The formula from the CTU code for the effective area of the cushion is as follows:<\/p>\n\n\n\n

A = (bDB<\/sub> – \u03c0 * d\/2) * (hDB<\/sub> – \u03c0 * d\/2)<\/strong><\/p>\n\n\n\n

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