{"id":680276,"date":"2023-11-06T14:15:49","date_gmt":"2023-11-06T13:15:49","guid":{"rendered":"https:\/\/rothschenk.de\/epizoda-37-rozlozenie-nakladu-na-nakladnych-vozidlach-ako-spravne-vypocitat-hodnoty\/"},"modified":"2025-06-30T16:59:44","modified_gmt":"2025-06-30T14:59:44","slug":"epizoda-37-rozlozenie-nakladu-na-nakladnych-vozidlach-ako-spravne-vypocitat-hodnoty","status":"publish","type":"post","link":"https:\/\/rothschenk.de\/sk\/epizoda-37-rozlozenie-nakladu-na-nakladnych-vozidlach-ako-spravne-vypocitat-hodnoty\/","title":{"rendered":"Epiz\u00f3da 37: Rozlo\u017eenie n\u00e1kladu na n\u00e1kladn\u00fdch vozidl\u00e1ch – ako spr\u00e1vne vypo\u010d\u00edta\u0165 hodnoty?"},"content":{"rendered":"\n

Rozlo\u017eenie n\u00e1kladu na n\u00e1kladn\u00fdch vozidl\u00e1ch opakovane predstavuje pre vodi\u010dov aj naklada\u010dov ve\u013ek\u00e9 v\u00fdzvy, ku ktor\u00fdm sa \u010dasto pristupuje s „polovi\u010dn\u00fdmi znalos\u0165ami“.<\/p>\n\n

Ak m\u00e1te z\u00e1kladn\u00e9 znalosti fyziky, probl\u00e9m sa d\u00e1 vyrie\u0161i\u0165 pomerne \u013eahko.<\/p>\n\n

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Vizualiz\u00e1cia rozlo\u017eenia za\u0165a\u017eenia<\/h2>\n\n
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Najjednoduch\u0161ie je predstavi\u0165 si, \u017ee n\u00e1kladn\u00e9 vozidlo stoj\u00ed so svojimi n\u00e1pravami na v\u00e1he.<\/p>\n\n\n\n

Ak je rozlo\u017eenie za\u0165a\u017eenia spr\u00e1vne, ukazovate\u013e stupnice je na nule alebo v strede.<\/p>\n<\/div>\n\n\n\n

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Ak by bola predn\u00e1 n\u00e1prava pre\u0165a\u017een\u00e1, \u013eav\u00e1 panva by sa zn\u00ed\u017eila a prav\u00e1 by sa zdvihla. To by bol jasn\u00fd d\u00f4sledok nespr\u00e1vneho rozlo\u017eenia za\u0165a\u017eenia. <\/p>\n\n\n\n

Cel\u00e1 vec by sa samozrejme obr\u00e1tila, ak by bola zadn\u00e1 n\u00e1prava pre\u0165a\u017een\u00e1.<\/p>\n<\/div>\n<\/div>\n\n

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Tento z\u00e1kladn\u00fd princ\u00edp aplikovan\u00fd na n\u00e1ves mo\u017eno zjednodu\u0161i\u0165 pridan\u00edm \u010fal\u0161ej v\u00e1hy na \u013eav\u00fa v\u00e1\u017eiacu misku, na ktorej spo\u010d\u00edva riadiaca a hnacia n\u00e1prava.<\/p>\n<\/div>\n<\/div>\n\n

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V predpisoch „DGUV70 Fahrzeuge“ nemeckej soci\u00e1lnej \u00farazovej pois\u0165ovne s\u00fa v koment\u00e1ri uveden\u00e9 tieto hrani\u010dn\u00e9 podmienky:K \u00a7 37 ods. 1: Po\u017eiadavka na dodr\u017eanie pr\u00edpustn\u00fdch hodn\u00f4t za\u0165a\u017eenia n\u00e1pravy je splnen\u00e1, ak: <\/p>\n\n\n\n

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  1. Pr\u00edpustn\u00e9 za\u0165a\u017eenie prednej n\u00e1pravy <\/strong>nie je prekro\u010den\u00e9<\/li>\n\n\n\n
  2. Pr\u00edpustn\u00e9 za\u0165a\u017eenie zadnej n\u00e1pravy <\/strong>nie je prekro\u010den\u00e9 a<\/li>\n\n\n\n
  3. Minim\u00e1lne za\u0165a\u017eenie riadenej<\/strong> n\u00e1pravy je najmenej 20 % momentovej hmotnosti vozidla (neplat\u00ed pre n\u00e1vesy).<\/li>\n<\/ol>\n\n\n\n

    Ak r\u00fdchlos\u0165 jazdy neprekro\u010d\u00ed 25 km\/h, minim\u00e1lne za\u0165a\u017eenie riadenej n\u00e1pravy sa m\u00f4\u017ee zn\u00ed\u017ei\u0165 na 10 % momentovej hmotnosti vozidla.<\/p>\n<\/div>\n<\/div>\n\n

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    Pl\u00e1n rozlo\u017eenia za\u0165a\u017eenia<\/h3>\n\n

    Hlavn\u00fdm z\u00e1kladom \u00favah je pl\u00e1n rozlo\u017eenia za\u0165a\u017eenia, ktor\u00fd je \u0161pecifick\u00fd pre ka\u017ed\u00fd typ vozidla. Predlohou pre obr\u00e1zok je program BG na v\u00fdpo\u010det pl\u00e1nov rozlo\u017eenia za\u0165a\u017eenia. Obr\u00e1zok bol upraven\u00fd na \u00fa\u010dely vizualiz\u00e1cie.(Pl\u00e1n rozlo\u017eenia n\u00e1kladu LVP 4.1 + Z\u00e1kladn\u00e9 z\u00e1sady zabezpe\u010denia n\u00e1kladu – BG Verkehr (bg-verkehr.de)<\/a>)<\/p>\n\n

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    Celkov\u00e9 \u0165a\u017eisko n\u00e1kladu mus\u00ed by\u0165 v\u017edy pod modrou \u010diarou. N\u00e1klad s maxim\u00e1lnou hmotnos\u0165ou 2 000 kg m\u00f4\u017ee by\u0165 umiestnen\u00fd kdeko\u013evek na lo\u017enej ploche. Ak v\u0161ak n\u00e1klad v\u00e1\u017ei 9 000 kg, \u0165a\u017eisko mus\u00ed by\u0165 vo vzdialenosti 3,40 m od prie\u010dky. \u010c\u00edm je n\u00e1klad \u0165a\u017e\u0161\u00ed, t\u00fdm je vo\u013en\u00fd priestor men\u0161\u00ed. <\/p>\n\n

    V grafe s\u00fa d\u00f4le\u017eit\u00e9 aj dve grafick\u00e9 osi. Os X ozna\u010duje d\u013a\u017eku lo\u017enej plochy a os Y u\u017eito\u010dn\u00e9 za\u0165a\u017eenie. <\/p>\n\n

    Pr\u00edklad: Ak cel\u00e9 bremeno v\u00e1\u017ei 7 000 kg, potom prejdite na Y=7to a potom do\u013eava na modr\u00fa \u010diaru.Je dvakr\u00e1t pretnut\u00e1, tak\u017ee \u0165a\u017eisko bremena m\u00f4\u017ee by\u0165 vo vzdialenosti 3 m a\u017e 5 m od koncovej steny. <\/p>\n\n

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    Z\u00e1kon p\u00e1kov\u00e9ho efektu<\/h2>\n\n

    Existuje v\u0161ak aj in\u00fd sp\u00f4sob ur\u010denia \u0165a\u017eiska. Na to si mus\u00edte spomen\u00fa\u0165 na z\u00e1kon p\u00e1ky <\/strong>. V\u00fdsledkom s\u00fa\u010dinu sily (hmotnosti bremena) a d\u013a\u017eky p\u00e1ky (vzdialenosti od \u010delnej steny k \u0165a\u017eisku n\u00e1kladovej jednotky) je moment. Momentov\u00fd k\u013e\u00fa\u010d funguje na rovnakom princ\u00edpe. V tomto pr\u00edpade v\u0161ak d\u013a\u017eka p\u00e1ky zost\u00e1va rovnak\u00e1 a silu mo\u017eno nastavi\u0165. <\/p>\n\n

    Pri pou\u017eit\u00ed tejto met\u00f3dy je potrebn\u00e9 pozna\u0165 polohu \u0165a\u017eiska <\/strong>na bremene. Najm\u00e4 v pr\u00edpade strojov a zariaden\u00ed kon\u0161truk\u010dn\u00e9 oddelenie \u010dasto neozna\u010d\u00ed polohu \u0165a\u017eiska alebo aspo\u0148 neposkytne v\u00fdkres, na ktorom by bola jeho poloha zn\u00e1zornen\u00e1. T\u00e1to inform\u00e1cia je rozhoduj\u00faca pre spr\u00e1vne nakladanie a upevnenie n\u00e1kladu. <\/p>\n\n

    Nasleduje fikt\u00edvny pr\u00edklad, ako mo\u017eno ur\u010di\u0165 \u0165a\u017eisko pre podobn\u00e9 n\u00e1kladov\u00e9 jednotky.<\/p>\n\n

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    Pri podobn\u00fdch n\u00e1kladoch, ako s\u00fa ve\u013ek\u00e9 vrecia, oktab\u00edny, IBC alebo n\u00e1pojov\u00e9 palety, sa \u0165a\u017eisko pos\u00fava s ka\u017ed\u00fdm radom n\u00e1kladu \u010falej dozadu. Pri tejto \u00favahe nemus\u00ed by\u0165 nevyhnutne zn\u00e1ma presn\u00e1 hmotnos\u0165. <\/p>\n\n

    Na konci nakladania mus\u00ed vodi\u010d a naklada\u010d vedie\u0165, \u010di je poloha celkov\u00e9ho \u0165a\u017eiska (zelen\u00e1 \u0161\u00edpka) pr\u00edpustn\u00e1 alebo nie. Ak t\u00e1to poloha nie je pr\u00edpustn\u00e1, bude sa musie\u0165 znovu nalo\u017ei\u0165, vylo\u017ei\u0165 a znovu nalo\u017ei\u0165. <\/p>\n\n

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    Matematick\u00e9 rie\u0161enie pr\u00edpadovej \u0161t\u00fadie<\/h3>\n\n

    Samozrejme, tento probl\u00e9m sa d\u00e1 vyrie\u0161i\u0165 aj matematicky. Nie je to \u0165a\u017ek\u00e9, ale je to n\u00e1ro\u010dn\u00e9. <\/p>\n\n

    Vezmite hmotnos\u0165 (v kg) prv\u00e9ho bremena a vyn\u00e1sobte ju vzdialenos\u0165ou (v m) medzi \u0165a\u017eiskom a prednou stenou. Ak s\u00fa n\u00e1kladov\u00e9 jednotky rovnak\u00e9ho typu, mo\u017eno pou\u017ei\u0165 aj cel\u00fd rad bremien. <\/p>\n\n

    Druh\u00e9 za\u0165a\u017eenie vyn\u00e1soben\u00e9 novou vzdialenos\u0165ou \u0165a\u017eiska sa potom pripo\u010d\u00edta k prv\u00e9mu v\u00fdsledku a tak \u010falej, k\u00fdm sa nevypo\u010d\u00edtaj\u00fa v\u0161etky jednotky za\u0165a\u017eenia.<\/p>\n\n

    Celkov\u00fd v\u00fdsledok sa vydel\u00ed celkovou hmotnos\u0165ou n\u00e1kladu.<\/p>\n\n

    V\u00fdsledkom je vzdialenos\u0165 medzi celkov\u00fdm \u0165a\u017eiskom n\u00e1kladu a prednou stenou.<\/p>\n\n

    Pre \u0161tandardn\u00fd n\u00e1ves s maxim\u00e1lnym u\u017eito\u010dn\u00fdm za\u0165a\u017een\u00edm mus\u00ed by\u0165 t\u00e1to vzdialenos\u0165 medzi 6,80 a 7,2.<\/p>\n\n

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    T\u00ed z na\u0161ich \u010ditate\u013eov, ktor\u00ed s\u00fa dostato\u010dne obozn\u00e1men\u00ed s programom Excel, si m\u00f4\u017eu pr\u00e1cu s v\u00fdpo\u010dtom u\u013eah\u010di\u0165. M\u00f4\u017eu si vytvori\u0165 tabu\u013eku, ktor\u00e1 im po zadan\u00ed \u00fadajov poskytne v\u00fdsledok. <\/p>\n\n

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    Z\u00e1ver<\/h2>\n\n

    S t\u00fdmito z\u00e1kladn\u00fdmi znalos\u0165ami by malo by\u0165 mo\u017en\u00e9 spr\u00e1vne ulo\u017ei\u0165 n\u00e1klad do takej miery, aby sa predi\u0161lo priestupku proti bezpe\u010dnosti prev\u00e1dzky a dopravy.<\/p>\n\n

    V\u017edy je potrebn\u00e9 ma\u0165 na pam\u00e4ti, \u017ee okrem spr\u00e1vneho deliktu by to mohlo vies\u0165 aj k trestn\u00e9mu \u010dinu. Konkr\u00e9tne, ak nespr\u00e1vne nalo\u017een\u00e9 vozidlo sp\u00f4sob\u00ed nehodu so zraneniami, smrte\u013en\u00fdmi n\u00e1sledkami alebo ve\u013ek\u00fdmi \u0161kodami na majetku. <\/p>\n\n

    V\u0161etci sa tomu chceme vyhn\u00fa\u0165, preto\u017ee ako \u00fa\u010dastn\u00edkov cestnej prem\u00e1vky n\u00e1s to m\u00f4\u017ee kedyko\u013evek postihn\u00fa\u0165.<\/p>\n\n

    V\u00e1\u0161, Sigurd Ehringer<\/p>\n\n

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    << Predch\u00e1dzaj\u00faci \u010dl\u00e1nokEpisode 36: Code XL – Load on the front wall – What needs to be considered?<\/a><\/p>\n<\/div>\n\n\n\n

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    K \u010fal\u0161iemu pr\u00edspevku >> Epiz\u00f3da 38: Ako funguje proti\u0161mykov\u00e1 podlo\u017eka? – \u010cas\u0165 1: Princ\u00edp fungovania <\/a><\/p>\n<\/div>\n<\/div>\n\n

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    Sigurd Ehringer<\/p>

    \u2714 VDI-zertifizierter Ausbilder f\u00fcr Ladungssicherung\r\n\u2714 Fachbuch-Autor\r\n\u2714 8 Jahre Projektmanager\r\n\u2714 12 Jahre bei der Bundeswehr (Kompaniechef)\r\n\u2714 20 Jahre Vertriebserfahrung\r\n\u2714 seit 1996 Berater\/Ausbilder in der Logistik\r\n\u2714 44 Jahre Ausbilder\/Trainer in verschiedenen Bereichen —>\r\n\r\nIn einer Reihe von Fachbeitr\u00e4gen aus der Praxis, zu Themen rund um den Container und LKW, erhalten Sie Profiwissen aus erster Hand. Wie sichert man Ladung korrekt und was sind die Grundlagen der Ladungssicherung?\r\nErarbeitet und vorgestellt werden sie von Sigurd Ehringer, Inhaber von SE-LogCon<\/a>.<\/p><\/div><\/div><\/div>\n\n\n\n

    <\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

    Rozlo\u017eenie n\u00e1kladu na n\u00e1kladn\u00fdch vozidl\u00e1ch opakovane predstavuje pre vodi\u010dov aj naklada\u010dov ve\u013ek\u00e9 v\u00fdzvy, ku ktor\u00fdm sa \u010dasto pristupuje s „polovi\u010dn\u00fdmi znalos\u0165ami“. Ak m\u00e1te z\u00e1kladn\u00e9 znalosti fyziky, probl\u00e9m sa d\u00e1 vyrie\u0161i\u0165 pomerne \u013eahko. Vizualiz\u00e1cia rozlo\u017eenia za\u0165a\u017eenia Najjednoduch\u0161ie je predstavi\u0165 si, \u017ee n\u00e1kladn\u00e9 vozidlo stoj\u00ed so svojimi n\u00e1pravami na v\u00e1he. Ak je rozlo\u017eenie za\u0165a\u017eenia spr\u00e1vne, ukazovate\u013e stupnice […]<\/p>\n","protected":false},"author":1536,"featured_media":680295,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[872,874,892],"tags":[],"class_list":["post-680276","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cargo-blog-sk","category-fyzicka-stranka-sk","category-lorry-sk"],"acf":[],"yoast_head":"\nRozlo\u017eenie n\u00e1kladu na n\u00e1kladn\u00fdch vozidl\u00e1ch | V\u00fdpo\u010dty | Pr\u00edklady - Rothschenk<\/title>\n<meta name=\"description\" content=\"Ak\u00e9 za\u0165a\u017eenia vznikaj\u00fa? \u2714 \u010co mus\u00edte zoh\u013eadni\u0165 pri nakladan\u00ed? \u2714 K\u00f3d XL \u2714 Be\u017en\u00e9 chyby \u2714 Po\u0161kodenie \u2714 Praktick\u00e9 pr\u00edklady + rie\u0161enia\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/rothschenk.de\/sk\/epizoda-37-rozlozenie-nakladu-na-nakladnych-vozidlach-ako-spravne-vypocitat-hodnoty\/\" \/>\n<meta property=\"og:locale\" content=\"sk_SK\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Rozlo\u017eenie n\u00e1kladu na n\u00e1kladn\u00fdch vozidl\u00e1ch | V\u00fdpo\u010dty | Pr\u00edklady - Rothschenk\" \/>\n<meta property=\"og:description\" content=\"Ak\u00e9 za\u0165a\u017eenia vznikaj\u00fa? 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