{"id":680901,"date":"2021-08-06T09:52:29","date_gmt":"2021-08-06T07:52:29","guid":{"rendered":"https:\/\/rothschenk.de\/epizoda-9-zrychlenie\/"},"modified":"2025-06-30T17:02:48","modified_gmt":"2025-06-30T15:02:48","slug":"epizoda-9-zrychlenie","status":"publish","type":"post","link":"https:\/\/rothschenk.de\/sk\/epizoda-9-zrychlenie\/","title":{"rendered":"Epiz\u00f3da 9: Zr\u00fdchlenie"},"content":{"rendered":"\n

Zr\u00fdchlenie je fyzik\u00e1lny jav, ktor\u00fd n\u00e1s neust\u00e1le obklopuje. \u010casto si to neuvedomujeme, a ak \u00e1no, tak to bol\u00ed, napr. ke\u010f si klepnete kladivom po palci. <\/p>\n\n

T\u00fdmto blogom LaSi by som chcel na\u010drtn\u00fa\u0165 hranice od ka\u017edodenn\u00fdch situ\u00e1ci\u00ed a\u017e po \u0161peci\u00e1lne po\u017eiadavky na prepravu n\u00e1morn\u00fdm kontajnerom alebo n\u00e1kladn\u00fdm autom.<\/p>\n\n

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V\u00fdpo\u010det zr\u00fdchlenia<\/h2>\n\n
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Vo fyzike hovor\u00edme o rovnomerne zr\u00fdchlenom posune s po\u010diato\u010dnou r\u00fdchlos\u0165ou alebo bez nej.<\/p>\n\n\n\n

Zr\u00fdchlenie (a) sa vypo\u010d\u00edta vydelen\u00edm r\u00fdchlosti (v) \u010dasom (t). Zr\u00fdchlenie m\u00e1 jednotku m\/s2<\/sup>. <\/p>\n\n\n\n

Zmeny r\u00fdchlosti s\u00fa \u010dasto sp\u00f4soben\u00e9 brzden\u00edm, ktor\u00e9 sa vo fyzike ozna\u010duje ako spomalenie. V\u00fdpo\u010det je rovnak\u00fd, men\u00ed sa len znamienko z + na – . <\/p>\n<\/div>\n<\/div>\n\n

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V praxi je d\u00f4le\u017eit\u00fd aj prvok hmotnosti. Pri ot\u00e1zke o zaisten\u00ed n\u00e1kladu sa u\u017e pravdepodobne jeden alebo dvaja \u013eudia dozvedeli: je to tak\u00e9 \u0165a\u017ek\u00e9, \u017ee sa to v\u00f4bec nem\u00f4\u017ee pohn\u00fa\u0165. A pr\u00e1ve v tom spo\u010d\u00edva probl\u00e9m, preto\u017ee hmotnos\u0165 m\u00e1 t\u00fa vlastnos\u0165, \u017ee chce zachova\u0165 svoj s\u00fa\u010dasn\u00fd stav a akejko\u013evek zmene sa br\u00e1ni silou. <\/p>\n\n

Tento jav m\u00f4\u017ee ka\u017ed\u00fd pozorova\u0165 na p\u00e1se pri pokladni v diskontnom obchode. Polo\u017eky sa pos\u00favaj\u00fa zaka\u017ed\u00fdm, ke\u010f sa dopravn\u00edkov\u00fd p\u00e1s pohne dopredu alebo spomal\u00ed. Naskladan\u00fd n\u00e1kupn\u00fd tovar sa pos\u00fava, f\u013ea\u0161e sa prevracaj\u00fa alebo sa za\u010dn\u00fa kot\u00fa\u013ea\u0165. Presne to ist\u00e9 sa deje po\u010das prepravy. <\/p>\n\n

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Pr\u00edpadov\u00e1 \u0161t\u00fadia<\/h3>\n\n

Vz\u0165ah medzi hmotnos\u0165ou a zr\u00fdchlen\u00edm si m\u00f4\u017ee ka\u017ed\u00fd vysk\u00fa\u0161a\u0165 v praxi na nasleduj\u00facom pr\u00edklade.<\/p>\n\n

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F\u00e1za 1:<\/h4>\n\n\n\n

Vezmite 120 mm klinec a 500 g kladivo. Polo\u017ete \u0161pi\u010dku klinca na kv\u00e1der a potom prilo\u017ete kladivo na hlavu klinca. V\u00fdsledkom je, \u017ee klinec bude minim\u00e1lne a nepatrne tla\u010di\u0165 do m\u00e4kk\u00e9ho dreva. Ak kladivo op\u00e4\u0165 vyberiete, klinec sa zvy\u010dajne op\u00e4\u0165 prevr\u00e1ti. Z fyzik\u00e1lneho h\u013eadiska je \u00fa\u010dinn\u00e1 len sila vypl\u00fdvaj\u00faca z hmotnosti kladiva vyn\u00e1soben\u00e1 gravita\u010dn\u00fdm zr\u00fdchlen\u00edm. <\/p>\n<\/div>\n<\/div>\n\n

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F\u00e1za 2:<\/h4>\n\n\n\n

Cvi\u010diaci zdvihne kladivo, zr\u00fdchli smerom k hlavi\u010dke klinca a d\u00fafa, \u017ee ju zasiahne. Toto dodato\u010dn\u00e9 zr\u00fdchlenie v\u00fdrazne zvy\u0161uje vytvoren\u00fa silu: <\/p>\n\n\n\n

Sila (F) = hmotnos\u0165 (m) * zr\u00fdchlenie (a)<\/p>\n<\/div>\n<\/div>\n\n

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F\u00e1za 3:<\/h4>\n\n\n\n

Pri \u00fadere sa kladivo prudko spomal\u00ed a sila zat\u013aka klinec do dreva. V z\u00e1vislosti od zr\u00fdchlenia, hmotnosti kladiva a trenia v dreve bude potrebn\u00fdch nieko\u013eko \u00faderov. <\/p>\n\n\n\n

V z\u00e1vislosti od situ\u00e1cie pou\u017eije cvi\u010diaci na vytvorenie po\u017eadovanej sily in\u00e9 kladivo. Samozrejme, je potrebn\u00e1 aj ur\u010dit\u00e1 technika. Ka\u017ed\u00fd, kto niekedy udrel „Luk\u00e1\u0161a“, vie, o \u010dom hovor\u00edm. <\/p>\n<\/div>\n<\/div>\n\n

Tento z\u00e1kladn\u00fd princ\u00edp sa skr\u00fdva za mnoh\u00fdmi situ\u00e1ciami pri zabezpe\u010dovan\u00ed z\u00e1\u0165a\u017ee. Napr\u00edklad, ke\u010f n\u00e1klad nie je ulo\u017een\u00fd tesne pri prie\u010dke a vodi\u010d n\u00e1kladn\u00e9ho vozidla mus\u00ed brzdi\u0165. N\u00e1klad sa pohybuje aktu\u00e1lnou r\u00fdchlos\u0165ou (f\u00e1za 2) a pri brzden\u00ed sa negat\u00edvne zr\u00fdch\u013euje (f\u00e1za 3). \u010c\u00edm v\u00e4\u010d\u0161ia je r\u00fdchlos\u0165 a \u010d\u00edm dlh\u0161ia je vzdialenos\u0165, na ktorej m\u00f4\u017ee nabra\u0165 hybnos\u0165, t\u00fdm v\u00e4\u010d\u0161ia je sila n\u00e1razu na \u010deln\u00fa stenu. <\/p>\n\n

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V\u00fdpo\u010det energie<\/h2>\n\n
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Z fyzik\u00e1lneho h\u013eadiska sa to vyjadruje pomocou vzorca na v\u00fdpo\u010det energie<\/strong>. Tento vzorec obsahuje aj kvadr\u00e1t r\u00fdchlosti (V2<\/sup><\/strong>). <\/p>\n\n\n\n

Mo\u017eno si niektor\u00ed z v\u00e1s spomen\u00fa na ot\u00e1zku z \u010dias, ke\u010f ste robili vodi\u010dsk\u00fd preukaz: Ako sa zmen\u00ed brzdn\u00e1 dr\u00e1ha, ke\u010f sa r\u00fdchlos\u0165 zdvojn\u00e1sob\u00ed?<\/p>\n\n\n\n

Odpove\u010f: zo\u0161tvorn\u00e1sob\u00ed sa <\/strong>. Je to sp\u00f4soben\u00e9 \u0161tvorcom r\u00fdchlosti. Energia (n\u00e1razov\u00e1 sila na predn\u00fa stenu) sa teda tie\u017e zvy\u0161uje s r\u00fdchlos\u0165ou, ktor\u00fa prejdete. <\/p>\n<\/div>\n<\/div>\n\n

Zr\u00fdchlenie a trenie<\/h2>\n\n

N\u00e1klad sa v\u017edy pohybuje, ke\u010f je zr\u00fdchlenie\/spomalenie v\u00e4\u010d\u0161ie ako trenie (koeficient trenia \u00b5<\/strong>). To znamen\u00e1, \u017ee pokia\u013e je zr\u00fdchlenie\/spomalenie men\u0161ie ako trenie medzi n\u00e1kladom a lo\u017enou plochou, n\u00e1klad zost\u00e1va na mieste. A\u017e ke\u010f s\u00fa v\u00e4\u010d\u0161ie, bremeno sa pohybuje trhavo. <\/p>\n\n

Spravidla nedoch\u00e1dza k postupn\u00e9mu prechodu. N\u00e1kladn\u00e9 jednotky ohrozen\u00e9 prevr\u00e1ten\u00edm sa v\u0161ak najprv<\/strong> za\u010dn\u00fa prevraca\u0165 a potom sa pos\u00fava\u0165<\/strong>. To sa d\u00e1 dobre demon\u0161trova\u0165 jazdn\u00fdmi sk\u00fa\u0161kami. <\/p>\n\n

Tento pr\u00edklad jasne ukazuje, \u017ee samotn\u00e9 proti\u0161mykov\u00e9 roho\u017ee<\/a> s\u00fa len teoretick\u00fdm zlep\u0161en\u00edm zabezpe\u010denia n\u00e1kladu. Musia sa doplni\u0165 \u010fal\u0161\u00edmi opatreniami, ako je napr\u00edklad viazanie. <\/p>\n\n

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Na lo\u017enej ploche stoj\u00ed stoh plastov\u00fdch boxov bez ak\u00e9hoko\u013evek dodato\u010dn\u00e9ho zabezpe\u010denia.<\/p>\n<\/div>\n\n\n\n

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Pri brzden\u00ed sa pos\u00favaj\u00fa dopredu bez nakl\u00e1\u0148ania.<\/p>\n<\/div>\n<\/div>\n\n

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Na dodato\u010dn\u00e9 zabezpe\u010denie n\u00e1kladu boli boxy umiestnen\u00e9 na proti\u0161mykov\u00fdch podlo\u017ek\u00e1ch.<\/p>\n<\/div>\n\n\n\n

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Pri brzden\u00ed sa okam\u017eite za\u010dn\u00fa prevraca\u0165.<\/p>\n<\/div>\n<\/div>\n\n

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Upevnenie n\u00e1kladu vzadu<\/h2>\n\n

Preto je d\u00f4le\u017eit\u00e9 zabr\u00e1ni\u0165 pohybu n\u00e1kladu<\/strong>. Najjednoduch\u0161\u00edm rie\u0161en\u00edm je pozit\u00edvne zaistenie. Treba v\u0161ak poznamena\u0165, \u017ee pohybu n\u00e1kladu sa mus\u00ed zabr\u00e1ni\u0165 vo v\u0161etk\u00fdch smeroch, preto\u017ee po pohybe v smere zr\u00fdchlenia\/spomalenia zvy\u010dajne nasleduje reakcia v opa\u010dnom smere. Niekedy sa spochyb\u0148uje upevnenie n\u00e1kladu vzadu. <\/p>\n\n

Hlavn\u00e1 \u010das\u0165 tohto sp\u00e4tn\u00e9ho zr\u00fdchlenia vznik\u00e1 ako reakcia na n\u00fadzov\u00e9 brzdenie (odrazov\u00fd efekt), preto\u017ee energia obsiahnut\u00e1 v z\u00e1\u0165a\u017ei nie je \u00faplne spotrebovan\u00e1.<\/p>\n\n

Nasleduj\u00faci pr\u00edklad je z cestn\u00e9ho testu. Hmotnos\u0165 n\u00e1kladu je pribli\u017ene 1 200 kg, r\u00fdchlos\u0165 pribli\u017ene 25 km\/h. <\/p>\n\n

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Po 5-sekundovom videoz\u00e1zname vozidlo prudko zabrzd\u00ed z r\u00fdchlosti 25 km\/h a n\u00e1klad s hmotnos\u0165ou 1 200 kg sa prevr\u00e1ti dopredu, preto\u017ee nebol pozit\u00edvne ulo\u017een\u00fd na hrazde.<\/p>\n<\/div>\n\n\n\n

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Bezprostredne potom doch\u00e1dza k pohybu (odrazov\u00e9mu efektu) smerom dozadu. Len o 2 sekundy nesk\u00f4r sa n\u00e1klad takmer \u00faplne prevr\u00e1til, preto\u017ee kinetick\u00e1 energia sa po\u010das n\u00fadzov\u00e9ho brzdenia \u00faplne nerozpt\u00fdlila. <\/p>\n<\/div>\n<\/div>\n\n

Preto mus\u00ed by\u0165 n\u00e1klad upevnen\u00fd aj vzadu.<\/strong><\/p>\n\n

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V n\u00e1kladnej doprave sa tento proces – \u00fapln\u00e9 zabrzdenie pri 0,8 g – zvy\u010dajne uskuto\u010dn\u00ed len raz. Pri preprave kontajnerovou lo\u010fou, ktor\u00e1 m\u00f4\u017ee pri valen\u00ed tie\u017e dosiahnu\u0165 zr\u00fdchlenie 0,8 g, m\u00f4\u017ee tento pohyb nasta\u0165 2 – 3-kr\u00e1t za min\u00fatu. Tieto nepretr\u017eit\u00e9 zr\u00fdchlenia s\u00fa jednou zo zvl\u00e1\u0161tnost\u00ed kontajnerov. <\/p>\n\n

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Z\u00e1ver<\/h2>\n\n

Zodpovedn\u00fd naklada\u010d\/dr\u017eite\u013e mus\u00ed preto pos\u00fadi\u0165 konkr\u00e9tnu situ\u00e1ciu na n\u00e1kladnom vozidle alebo v kontajneri, odhadn\u00fa\u0165 alebo vypo\u010d\u00edta\u0165 sily a potom prija\u0165 potrebn\u00e9 opatrenia. V\u00fdplne medzier musia by\u0165 samozrejme schopn\u00e9 odola\u0165 trval\u00e9mu za\u0165a\u017eeniu. Napr\u00edklad kart\u00f3nov\u00e9 medzery s\u00fa vo vlhkom prostred\u00ed dos\u0165 nevhodn\u00e9. <\/p>\n\n

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Bezpe\u010dnostn\u00e9 opatrenia v<\/strong> porad\u00ed pod\u013ea \u00fa\u010dinnosti s\u00fa:<\/p>\n\n\n\n

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  1. Ukladanie do tvarovan\u00e9ho obalu<\/li>\n\n\n\n
  2. Vypl\u0148te medzery, aby ste vytvorili tesn\u00e9 ulo\u017eenie<\/li>\n\n\n\n
  3. Priame pripevnenie je tie\u017e met\u00f3da tvarovej mont\u00e1\u017ee<\/li>\n\n\n\n
  4. Kombin\u00e1cia priameho upevnenia s proti\u0161mykov\u00fdmi roho\u017eami<\/li>\n\n\n\n
  5. V\u017edy kombinujte viazacie prostriedky s proti\u0161mykov\u00fdmi podlo\u017ekami<\/li>\n<\/ol>\n<\/div>\n<\/div>\n\n

    V\u00e1\u0161, Sigurd Ehringer<\/p>\n\n

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    << Predch\u00e1dzaj\u00faci pr\u00edspevokEpiz\u00f3da 8: Form-fit v kontajneri<\/a><\/p>\n<\/div>\n\n\n\n

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    Next post >> Episode 10: Force closure<\/a><\/p>\n<\/div>\n<\/div>\n\n

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    Sigurd Ehringer<\/p>

    \u2714 VDI-zertifizierter Ausbilder f\u00fcr Ladungssicherung\r\n\u2714 Fachbuch-Autor\r\n\u2714 8 Jahre Projektmanager\r\n\u2714 12 Jahre bei der Bundeswehr (Kompaniechef)\r\n\u2714 20 Jahre Vertriebserfahrung\r\n\u2714 seit 1996 Berater\/Ausbilder in der Logistik\r\n\u2714 44 Jahre Ausbilder\/Trainer in verschiedenen Bereichen —>\r\n\r\nIn einer Reihe von Fachbeitr\u00e4gen aus der Praxis, zu Themen rund um den Container und LKW, erhalten Sie Profiwissen aus erster Hand. Wie sichert man Ladung korrekt und was sind die Grundlagen der Ladungssicherung?\r\nErarbeitet und vorgestellt werden sie von Sigurd Ehringer, Inhaber von SE-LogCon<\/a>.<\/p><\/div><\/div><\/div>\n\n\n\n

    <\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

    Zr\u00fdchlenie je fyzik\u00e1lny jav, ktor\u00fd n\u00e1s neust\u00e1le obklopuje. \u010casto si to neuvedomujeme, a ak \u00e1no, tak to bol\u00ed, napr. ke\u010f si klepnete kladivom po palci. T\u00fdmto blogom LaSi by som chcel na\u010drtn\u00fa\u0165 hranice od ka\u017edodenn\u00fdch situ\u00e1ci\u00ed a\u017e po \u0161peci\u00e1lne po\u017eiadavky na prepravu n\u00e1morn\u00fdm kontajnerom alebo n\u00e1kladn\u00fdm autom. V\u00fdpo\u010det zr\u00fdchlenia Vo fyzike hovor\u00edme o rovnomerne zr\u00fdchlenom […]<\/p>\n","protected":false},"author":1536,"featured_media":680912,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[872,874,892],"tags":[],"class_list":["post-680901","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cargo-blog-sk","category-fyzicka-stranka-sk","category-lorry-sk"],"acf":[],"yoast_head":"\nZr\u00fdchlenie - ak\u00e9 s\u00fa nebezpe\u010denstv\u00e1? - Rothschenk<\/title>\n<meta name=\"description\" content=\"Technick\u00fd \u010dl\u00e1nok o zr\u00fdchlen\u00ed prepravy tovaru. 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